Write in Slope-Intercept Form x+3y>=6

$x + 3 y \geq 6$

Solve for $y$ .

Subtract $x$ from both sides of the inequality.

$3 y \geq 6 - x$

Divide each term in $3 y \geq 6 - x$ by $3$ and simplify.

Divide each term in $3 y \geq 6 - x$ by $3$ .

$\frac{3 y}{3} \geq \frac{6}{3} + \frac{- x}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} \geq \frac{6}{3} + \frac{- x}{3}$

Divide $y$ by $1$ .

$y \geq \frac{6}{3} + \frac{- x}{3}$

Simplify the right side.

Simplify each term.

Divide $6$ by $3$ .

$y \geq 2 + \frac{- x}{3}$

Move the negative in front of the fraction.

$y \geq 2 - \frac{x}{3}$

Rearrange terms.

$y \geq - \frac{x}{3} + 2$

Reorder terms.

$y \geq - (\frac{1}{3} x) + 2$

Remove parentheses.

$y \geq - \frac{1}{3} x + 2$