Write in Standard Form 2x^2+2y^2-8=0

$2 x^{2} + 2 y^{2} - 8 = 0$

Step 1

Add $8$ to both sides of the equation.

$2 x^{2} + 2 y^{2} = 8$

Step 2

Divide both sides of the equation by $2$ .

$x^{2} + y^{2} = 4$

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