Write in Standard Form (2x+5)(x-1)=-6

$(2 x + 5) (x - 1) = - 6$

Add $6$ to both sides of the equation.

$(2 x + 5) (x - 1) + 6 = 0$

Simplify $(2 x + 5) (x - 1) + 6$ .

Simplify each term.

Expand $(2 x + 5) (x - 1)$ using the FOIL Method.

Apply the distributive property.

$2 x (x - 1) + 5 (x - 1) + 6 = 0$

Apply the distributive property.

$2 x \cdot x + 2 x \cdot - 1 + 5 (x - 1) + 6 = 0$

Apply the distributive property.

$2 x \cdot x + 2 x \cdot - 1 + 5 x + 5 \cdot - 1 + 6 = 0$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$2 (x \cdot x) + 2 x \cdot - 1 + 5 x + 5 \cdot - 1 + 6 = 0$

Multiply $x$ by $x$ .

$2 x^{2} + 2 x \cdot - 1 + 5 x + 5 \cdot - 1 + 6 = 0$

Multiply $- 1$ by $2$ .

$2 x^{2} - 2 x + 5 x + 5 \cdot - 1 + 6 = 0$

Multiply $5$ by $- 1$ .

$2 x^{2} - 2 x + 5 x - 5 + 6 = 0$

Add $- 2 x$ and $5 x$ .

$2 x^{2} + 3 x - 5 + 6 = 0$

Add $- 5$ and $6$ .

$2 x^{2} + 3 x + 1 = 0$

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

The standard form is $2 x^{2} + 3 x + 1$ .

$2 x^{2} + 3 x + 1 = 0$