Write as a Set of Linear Factors 12x+1=3(4x+1)-2

$12 x + 1 = 3 (4 x + 1) - 2$

Step 1

Move all the expressions to the left side of the equation.

Subtract $3 (4 x + 1)$ from both sides of the equation.

$12 x + 1 - 3 (4 x + 1) = - 2$

Add $2$ to both sides of the equation.

$12 x + 1 - 3 (4 x + 1) + 2 = 0$

Step 2

Simplify $12 x + 1 - 3 (4 x + 1) + 2$ .

Simplify each term.

Apply the distributive property.

$12 x + 1 - 3 (4 x) - 3 \cdot 1 + 2 = 0$

Multiply $4$ by $- 3$ .

$12 x + 1 - 12 x - 3 \cdot 1 + 2 = 0$

Multiply $- 3$ by $1$ .

$12 x + 1 - 12 x - 3 + 2 = 0$

Combine the opposite terms in $12 x + 1 - 12 x - 3 + 2$ .

Subtract $12 x$ from $12 x$ .

$0 + 1 - 3 + 2 = 0$

Add $0$ and $1$ .

$1 - 3 + 2 = 0$

Subtract $3$ from $1$ .

$- 2 + 2 = 0$

Add $- 2$ and $2$ .

$0 = 0$