Write in Standard Form 3x-y^2=4x+25

$3 x - y^{2} = 4 x + 25$

Solve for $y$ .

Move all terms not containing $y$ to the right side of the equation.

Subtract $3 x$ from both sides of the equation.

$- y^{2} = 4 x + 25 - 3 x$

Subtract $3 x$ from $4 x$ .

$- y^{2} = x + 25$

Divide each term in $- y^{2} = x + 25$ by $- 1$ and simplify.

Divide each term in $- y^{2} = x + 25$ by $- 1$ .

$\frac{- y^{2}}{- 1} = \frac{x}{- 1} + \frac{25}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y^{2}}{1} = \frac{x}{- 1} + \frac{25}{- 1}$

Divide $y^{2}$ by $1$ .

$y^{2} = \frac{x}{- 1} + \frac{25}{- 1}$

Simplify the right side.

Simplify each term.

Move the negative one from the denominator of $\frac{x}{- 1}$ .

$y^{2} = - 1 \cdot x + \frac{25}{- 1}$

Rewrite $- 1 \cdot x$ as $- x$ .

$y^{2} = - x + \frac{25}{- 1}$

Divide $25$ by $- 1$ .

$y^{2} = - x - 25$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$y = \pm \sqrt{- x - 25}$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$y = \sqrt{- x - 25}$

Next, use the negative value of the $\pm$ to find the second solution.

$y = - \sqrt{- x - 25}$

The complete solution is the result of both the positive and negative portions of the solution.

$y = \sqrt{- x - 25}$

$y = - \sqrt{- x - 25}$

$y = \sqrt{- x - 25}$

$y = - \sqrt{- x - 25}$

$y = \sqrt{- x - 25}$

$y = - \sqrt{- x - 25}$

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$y = a x^{2} + b x + c$

The standard form is $\sqrt{- x - 25}, - \sqrt{- x - 25}$ .

$y = \sqrt{- x - 25}$

$y = - \sqrt{- x - 25}$