Write in Standard Form m^2-6m+5=4m^2-8

$m^{2} - 6 m + 5 = 4 m^{2} - 8$

Move all the expressions to the left side of the equation.

Subtract $4 m^{2}$ from both sides of the equation.

$m^{2} - 6 m + 5 - 4 m^{2} = - 8$

Add $8$ to both sides of the equation.

$m^{2} - 6 m + 5 - 4 m^{2} + 8 = 0$

Simplify $m^{2} - 6 m + 5 - 4 m^{2} + 8$ .

Subtract $4 m^{2}$ from $m^{2}$ .

$- 3 m^{2} - 6 m + 5 + 8 = 0$

Add $5$ and $8$ .

$- 3 m^{2} - 6 m + 13 = 0$

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

The standard form is $- 3 m^{2} - 6 m + 13$ .

$- 3 m^{2} - 6 m + 13 = 0$