Write in Standard Form (x+4)(x-5)+3=0

$(x + 4) (x - 5) + 3 = 0$

Step 1

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 2

Simplify each term.

Expand $(x + 4) (x - 5)$ using the FOIL Method.

Apply the distributive property.

$x (x - 5) + 4 (x - 5) + 3 = 0$

Apply the distributive property.

$x \cdot x + x \cdot - 5 + 4 (x - 5) + 3 = 0$

Apply the distributive property.

$x \cdot x + x \cdot - 5 + 4 x + 4 \cdot - 5 + 3 = 0$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot - 5 + 4 x + 4 \cdot - 5 + 3 = 0$

Move $- 5$ to the left of $x$ .

$x^{2} - 5 \cdot x + 4 x + 4 \cdot - 5 + 3 = 0$

Multiply $4$ by $- 5$ .

$x^{2} - 5 x + 4 x - 20 + 3 = 0$

Add $- 5 x$ and $4 x$ .

$x^{2} - x - 20 + 3 = 0$

Step 3

Add $- 20$ and $3$ .

$x^{2} - x - 17 = 0$

Step 4