Write in y=mx+b Form -8x=1-4y

$- 8 x = 1 - 4 y$

Step 1

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Step 2

Rewrite in slope-intercept form.

Rewrite the equation as $1 - 4 y = - 8 x$ .

$1 - 4 y = - 8 x$

Subtract $1$ from both sides of the equation.

$- 4 y = - 8 x - 1$

Divide each term in $- 4 y = - 8 x - 1$ by $- 4$ and simplify.

Divide each term in $- 4 y = - 8 x - 1$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{- 8 x}{- 4} + \frac{- 1}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{- 8 x}{- 4} + \frac{- 1}{- 4}$

Divide $y$ by $1$ .

$y = \frac{- 8 x}{- 4} + \frac{- 1}{- 4}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 8$ and $- 4$ .

Factor $- 4$ out of $- 8 x$ .

$y = \frac{- 4 (2 x)}{- 4} + \frac{- 1}{- 4}$

Cancel the common factors.

Factor $- 4$ out of $- 4$ .

$y = \frac{- 4 (2 x)}{- 4 (1)} + \frac{- 1}{- 4}$

Cancel the common factor.

$y = \frac{- 4 (2 x)}{- 4 \cdot 1} + \frac{- 1}{- 4}$

Rewrite the expression.

$y = \frac{2 x}{1} + \frac{- 1}{- 4}$

Divide $2 x$ by $1$ .

$y = 2 x + \frac{- 1}{- 4}$

Dividing two negative values results in a positive value.

$y = 2 x + \frac{1}{4}$