Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
Make use of GCD Calculator to determine the Greatest Common Divisor of 10, 615, 491, 612 i.e. 1 largest integer that divides all the numbers equally.
GCD of 10, 615, 491, 612 is 1
GCD(10, 615, 491, 612) = 1
Ex: 10, 15, 20 (or) 24, 48, 96,45 (or) 78902, 89765, 12345
GCD of numbers 10, 615, 491, 612 is 1
GCD(10, 615, 491, 612) = 1
Given Input numbers are 10, 615, 491, 612
To find the GCD of numbers using factoring list out all the divisors of each number
Divisors of 10
List of positive integer divisors of 10 that divides 10 without a remainder.
1, 2, 5, 10
Divisors of 615
List of positive integer divisors of 615 that divides 615 without a remainder.
1, 3, 5, 15, 41, 123, 205, 615
Divisors of 491
List of positive integer divisors of 491 that divides 491 without a remainder.
1, 491
Divisors of 612
List of positive integer divisors of 612 that divides 612 without a remainder.
1, 2, 3, 4, 6, 9, 12, 17, 18, 34, 36, 51, 68, 102, 153, 204, 306, 612
Greatest Common Divisior
We found the divisors of 10, 615, 491, 612 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 10, 615, 491, 612 is 1.
Therefore, GCD of numbers 10, 615, 491, 612 is 1
Given Input Data is 10, 615, 491, 612
Make a list of Prime Factors of all the given numbers initially
Prime Factorization of 10 is 2 x 5
Prime Factorization of 615 is 3 x 5 x 41
Prime Factorization of 491 is 491
Prime Factorization of 612 is 2 x 2 x 3 x 3 x 17
The above numbers do not have any common prime factor. So GCD is 1
Step1:
Let's calculate the GCD of first two numbers
The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)
LCM(10, 615) = 1230
GCD(10, 615) = ( 10 x 615 ) / 1230
GCD(10, 615) = 6150 / 1230
GCD(10, 615) = 5
Step2:
Here we consider the GCD from the above i.e. 5 as first number and the next as 491
The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)
LCM(5, 491) = 2455
GCD(5, 491) = ( 5 x 491 ) / 2455
GCD(5, 491) = 2455 / 2455
GCD(5, 491) = 1
Step3:
Here we consider the GCD from the above i.e. 1 as first number and the next as 612
The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)
LCM(1, 612) = 612
GCD(1, 612) = ( 1 x 612 ) / 612
GCD(1, 612) = 612 / 612
GCD(1, 612) = 1
GCD of 10, 615, 491, 612 is 1
Here are some samples of GCD of Numbers calculations.
1. What is the GCD of 10, 615, 491, 612?
GCD of 10, 615, 491, 612 is 1
2. Where do I get the detailed procedure to find GCD of 10, 615, 491, 612?
You can find a detailed procedure to find GCD of 10, 615, 491, 612 on our page.
3. How to find GCD of 10, 615, 491, 612 on a calculator?
You can find the GCD of 10, 615, 491, 612 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.