GCD of 160, 570, 815 Calculator

Given Input numbers are 160, 570, 815

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 160

List of positive integer divisors of 160 that divides 160 without a remainder.

1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 80, 160

Divisors of 570

List of positive integer divisors of 570 that divides 570 without a remainder.

1, 2, 3, 5, 6, 10, 15, 19, 30, 38, 57, 95, 114, 190, 285, 570

Divisors of 815

List of positive integer divisors of 815 that divides 815 without a remainder.

1, 5, 163, 815

Greatest Common Divisior

We found the divisors of 160, 570, 815 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 160, 570, 815 is 5.

Therefore, GCD of numbers 160, 570, 815 is 5

Given Input Data is 160, 570, 815

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 160 is 2 x 2 x 2 x 2 x 2 x 5

Prime Factorization of 570 is 2 x 3 x 5 x 19

Prime Factorization of 815 is 5 x 163

Highest common occurrences in the given inputs are 5¹

Multiplying them we get the GCD as 5

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(160, 570) = 9120

GCD(160, 570) = ( 160 x 570 ) / 9120

GCD(160, 570) = 91200 / 9120

GCD(160, 570) = 10

Step2:

Here we consider the GCD from the above i.e. 10 as first number and the next as 815

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(10, 815) = 1630

GCD(10, 815) = ( 10 x 815 ) / 1630

GCD(10, 815) = 8150 / 1630

GCD(10, 815) = 5

GCD of 160, 570, 815 is 5

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1. What is the GCD of 160, 570, 815?

GCD of 160, 570, 815 is 5

2. Where do I get the detailed procedure to find GCD of 160, 570, 815?

You can find a detailed procedure to find GCD of 160, 570, 815 on our page.

3. How to find GCD of 160, 570, 815 on a calculator?

You can find the GCD of 160, 570, 815 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.