GCD of 225, 495, 150 Calculator

Given Input numbers are 225, 495, 150

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 225

List of positive integer divisors of 225 that divides 225 without a remainder.

1, 3, 5, 9, 15, 25, 45, 75, 225

Divisors of 495

List of positive integer divisors of 495 that divides 495 without a remainder.

1, 3, 5, 9, 11, 15, 33, 45, 55, 99, 165, 495

Divisors of 150

List of positive integer divisors of 150 that divides 150 without a remainder.

1, 2, 3, 5, 6, 10, 15, 25, 30, 50, 75, 150

Greatest Common Divisior

We found the divisors of 225, 495, 150 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 225, 495, 150 is 15.

Therefore, GCD of numbers 225, 495, 150 is 15

Given Input Data is 225, 495, 150

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 225 is 3 x 3 x 5 x 5

Prime Factorization of 495 is 3 x 3 x 5 x 11

Prime Factorization of 150 is 2 x 3 x 5 x 5

Highest common occurrences in the given inputs are 3¹ x 5¹

Multiplying them we get the GCD as 15

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(225, 495) = 2475

GCD(225, 495) = ( 225 x 495 ) / 2475

GCD(225, 495) = 111375 / 2475

GCD(225, 495) = 45

Step2:

Here we consider the GCD from the above i.e. 45 as first number and the next as 150

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(45, 150) = 450

GCD(45, 150) = ( 45 x 150 ) / 450

GCD(45, 150) = 6750 / 450

GCD(45, 150) = 15

GCD of 225, 495, 150 is 15

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1. What is the GCD of 225, 495, 150?

GCD of 225, 495, 150 is 15

2. Where do I get the detailed procedure to find GCD of 225, 495, 150?

You can find a detailed procedure to find GCD of 225, 495, 150 on our page.

3. How to find GCD of 225, 495, 150 on a calculator?

You can find the GCD of 225, 495, 150 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.