GCD of 228, 520, 250 Calculator

Given Input numbers are 228, 520, 250

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 228

List of positive integer divisors of 228 that divides 228 without a remainder.

1, 2, 3, 4, 6, 12, 19, 38, 57, 76, 114, 228

Divisors of 520

List of positive integer divisors of 520 that divides 520 without a remainder.

1, 2, 4, 5, 8, 10, 13, 20, 26, 40, 52, 65, 104, 130, 260, 520

Divisors of 250

List of positive integer divisors of 250 that divides 250 without a remainder.

1, 2, 5, 10, 25, 50, 125, 250

Greatest Common Divisior

We found the divisors of 228, 520, 250 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 228, 520, 250 is 2.

Therefore, GCD of numbers 228, 520, 250 is 2

Given Input Data is 228, 520, 250

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 228 is 2 x 2 x 3 x 19

Prime Factorization of 520 is 2 x 2 x 2 x 5 x 13

Prime Factorization of 250 is 2 x 5 x 5 x 5

Highest common occurrences in the given inputs are 2¹

Multiplying them we get the GCD as 2

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(228, 520) = 29640

GCD(228, 520) = ( 228 x 520 ) / 29640

GCD(228, 520) = 118560 / 29640

GCD(228, 520) = 4

Step2:

Here we consider the GCD from the above i.e. 4 as first number and the next as 250

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(4, 250) = 500

GCD(4, 250) = ( 4 x 250 ) / 500

GCD(4, 250) = 1000 / 500

GCD(4, 250) = 2

GCD of 228, 520, 250 is 2

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1. What is the GCD of 228, 520, 250?

GCD of 228, 520, 250 is 2

2. Where do I get the detailed procedure to find GCD of 228, 520, 250?

You can find a detailed procedure to find GCD of 228, 520, 250 on our page.

3. How to find GCD of 228, 520, 250 on a calculator?

You can find the GCD of 228, 520, 250 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.