GCD of 236, 744, 516 Calculator

Given Input numbers are 236, 744, 516

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 236

List of positive integer divisors of 236 that divides 236 without a remainder.

1, 2, 4, 59, 118, 236

Divisors of 744

List of positive integer divisors of 744 that divides 744 without a remainder.

1, 2, 3, 4, 6, 8, 12, 24, 31, 62, 93, 124, 186, 248, 372, 744

Divisors of 516

List of positive integer divisors of 516 that divides 516 without a remainder.

1, 2, 3, 4, 6, 12, 43, 86, 129, 172, 258, 516

Greatest Common Divisior

We found the divisors of 236, 744, 516 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 236, 744, 516 is 4.

Therefore, GCD of numbers 236, 744, 516 is 4

Given Input Data is 236, 744, 516

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 236 is 2 x 2 x 59

Prime Factorization of 744 is 2 x 2 x 2 x 3 x 31

Prime Factorization of 516 is 2 x 2 x 3 x 43

Highest common occurrences in the given inputs are 2²

Multiplying them we get the GCD as 4

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(236, 744) = 43896

GCD(236, 744) = ( 236 x 744 ) / 43896

GCD(236, 744) = 175584 / 43896

GCD(236, 744) = 4

Step2:

Here we consider the GCD from the above i.e. 4 as first number and the next as 516

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(4, 516) = 516

GCD(4, 516) = ( 4 x 516 ) / 516

GCD(4, 516) = 2064 / 516

GCD(4, 516) = 4

GCD of 236, 744, 516 is 4

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1. What is the GCD of 236, 744, 516?

GCD of 236, 744, 516 is 4

2. Where do I get the detailed procedure to find GCD of 236, 744, 516?

You can find a detailed procedure to find GCD of 236, 744, 516 on our page.

3. How to find GCD of 236, 744, 516 on a calculator?

You can find the GCD of 236, 744, 516 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.