GCD of 264, 548, 804 Calculator

Given Input numbers are 264, 548, 804

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 264

List of positive integer divisors of 264 that divides 264 without a remainder.

1, 2, 3, 4, 6, 8, 11, 12, 22, 24, 33, 44, 66, 88, 132, 264

Divisors of 548

List of positive integer divisors of 548 that divides 548 without a remainder.

1, 2, 4, 137, 274, 548

Divisors of 804

List of positive integer divisors of 804 that divides 804 without a remainder.

1, 2, 3, 4, 6, 12, 67, 134, 201, 268, 402, 804

Greatest Common Divisior

We found the divisors of 264, 548, 804 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 264, 548, 804 is 4.

Therefore, GCD of numbers 264, 548, 804 is 4

Given Input Data is 264, 548, 804

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 264 is 2 x 2 x 2 x 3 x 11

Prime Factorization of 548 is 2 x 2 x 137

Prime Factorization of 804 is 2 x 2 x 3 x 67

Highest common occurrences in the given inputs are 2²

Multiplying them we get the GCD as 4

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(264, 548) = 36168

GCD(264, 548) = ( 264 x 548 ) / 36168

GCD(264, 548) = 144672 / 36168

GCD(264, 548) = 4

Step2:

Here we consider the GCD from the above i.e. 4 as first number and the next as 804

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(4, 804) = 804

GCD(4, 804) = ( 4 x 804 ) / 804

GCD(4, 804) = 3216 / 804

GCD(4, 804) = 4

GCD of 264, 548, 804 is 4

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1. What is the GCD of 264, 548, 804?

GCD of 264, 548, 804 is 4

2. Where do I get the detailed procedure to find GCD of 264, 548, 804?

You can find a detailed procedure to find GCD of 264, 548, 804 on our page.

3. How to find GCD of 264, 548, 804 on a calculator?

You can find the GCD of 264, 548, 804 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.