GCD of 307, 276, 489 Calculator

Given Input numbers are 307, 276, 489

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 307

List of positive integer divisors of 307 that divides 307 without a remainder.

1, 307

Divisors of 276

List of positive integer divisors of 276 that divides 276 without a remainder.

1, 2, 3, 4, 6, 12, 23, 46, 69, 92, 138, 276

Divisors of 489

List of positive integer divisors of 489 that divides 489 without a remainder.

1, 3, 163, 489

Greatest Common Divisior

We found the divisors of 307, 276, 489 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 307, 276, 489 is 1.

Therefore, GCD of numbers 307, 276, 489 is 1

Given Input Data is 307, 276, 489

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 307 is 307

Prime Factorization of 276 is 2 x 2 x 3 x 23

Prime Factorization of 489 is 3 x 163

The above numbers do not have any common prime factor. So GCD is 1

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(307, 276) = 84732

GCD(307, 276) = ( 307 x 276 ) / 84732

GCD(307, 276) = 84732 / 84732

GCD(307, 276) = 1

Step2:

Here we consider the GCD from the above i.e. 1 as first number and the next as 489

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(1, 489) = 489

GCD(1, 489) = ( 1 x 489 ) / 489

GCD(1, 489) = 489 / 489

GCD(1, 489) = 1

GCD of 307, 276, 489 is 1

Here are some samples of GCD of Numbers calculations.

• GCD of 132, 560, 693
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• GCD of 713, 163, 711
• GCD of 842, 151, 213
• GCD of 751, 620, 964

1. What is the GCD of 307, 276, 489?

GCD of 307, 276, 489 is 1

2. Where do I get the detailed procedure to find GCD of 307, 276, 489?

You can find a detailed procedure to find GCD of 307, 276, 489 on our page.

3. How to find GCD of 307, 276, 489 on a calculator?

You can find the GCD of 307, 276, 489 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.