Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
Make use of GCD Calculator to determine the Greatest Common Divisor of 321, 547, 71, 428 i.e. 1 largest integer that divides all the numbers equally.
GCD of 321, 547, 71, 428 is 1
GCD(321, 547, 71, 428) = 1
Ex: 10, 15, 20 (or) 24, 48, 96,45 (or) 78902, 89765, 12345
GCD of numbers 321, 547, 71, 428 is 1
GCD(321, 547, 71, 428) = 1
Given Input numbers are 321, 547, 71, 428
To find the GCD of numbers using factoring list out all the divisors of each number
Divisors of 321
List of positive integer divisors of 321 that divides 321 without a remainder.
1, 3, 107, 321
Divisors of 547
List of positive integer divisors of 547 that divides 547 without a remainder.
1, 547
Divisors of 71
List of positive integer divisors of 71 that divides 71 without a remainder.
1, 71
Divisors of 428
List of positive integer divisors of 428 that divides 428 without a remainder.
1, 2, 4, 107, 214, 428
Greatest Common Divisior
We found the divisors of 321, 547, 71, 428 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 321, 547, 71, 428 is 1.
Therefore, GCD of numbers 321, 547, 71, 428 is 1
Given Input Data is 321, 547, 71, 428
Make a list of Prime Factors of all the given numbers initially
Prime Factorization of 321 is 3 x 107
Prime Factorization of 547 is 547
Prime Factorization of 71 is 71
Prime Factorization of 428 is 2 x 2 x 107
The above numbers do not have any common prime factor. So GCD is 1
Step1:
Let's calculate the GCD of first two numbers
The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)
LCM(321, 547) = 175587
GCD(321, 547) = ( 321 x 547 ) / 175587
GCD(321, 547) = 175587 / 175587
GCD(321, 547) = 1
Step2:
Here we consider the GCD from the above i.e. 1 as first number and the next as 71
The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)
LCM(1, 71) = 71
GCD(1, 71) = ( 1 x 71 ) / 71
GCD(1, 71) = 71 / 71
GCD(1, 71) = 1
Step3:
Here we consider the GCD from the above i.e. 1 as first number and the next as 428
The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)
LCM(1, 428) = 428
GCD(1, 428) = ( 1 x 428 ) / 428
GCD(1, 428) = 428 / 428
GCD(1, 428) = 1
GCD of 321, 547, 71, 428 is 1
Here are some samples of GCD of Numbers calculations.
1. What is the GCD of 321, 547, 71, 428?
GCD of 321, 547, 71, 428 is 1
2. Where do I get the detailed procedure to find GCD of 321, 547, 71, 428?
You can find a detailed procedure to find GCD of 321, 547, 71, 428 on our page.
3. How to find GCD of 321, 547, 71, 428 on a calculator?
You can find the GCD of 321, 547, 71, 428 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.