GCD of 325, 483, 810 Calculator

Given Input numbers are 325, 483, 810

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 325

List of positive integer divisors of 325 that divides 325 without a remainder.

1, 5, 13, 25, 65, 325

Divisors of 483

List of positive integer divisors of 483 that divides 483 without a remainder.

1, 3, 7, 21, 23, 69, 161, 483

Divisors of 810

List of positive integer divisors of 810 that divides 810 without a remainder.

1, 2, 3, 5, 6, 9, 10, 15, 18, 27, 30, 45, 54, 81, 90, 135, 162, 270, 405, 810

Greatest Common Divisior

We found the divisors of 325, 483, 810 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 325, 483, 810 is 1.

Therefore, GCD of numbers 325, 483, 810 is 1

Given Input Data is 325, 483, 810

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 325 is 5 x 5 x 13

Prime Factorization of 483 is 3 x 7 x 23

Prime Factorization of 810 is 2 x 3 x 3 x 3 x 3 x 5

The above numbers do not have any common prime factor. So GCD is 1

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(325, 483) = 156975

GCD(325, 483) = ( 325 x 483 ) / 156975

GCD(325, 483) = 156975 / 156975

GCD(325, 483) = 1

Step2:

Here we consider the GCD from the above i.e. 1 as first number and the next as 810

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(1, 810) = 810

GCD(1, 810) = ( 1 x 810 ) / 810

GCD(1, 810) = 810 / 810

GCD(1, 810) = 1

GCD of 325, 483, 810 is 1

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• GCD of 487, 152, 866
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1. What is the GCD of 325, 483, 810?

GCD of 325, 483, 810 is 1

2. Where do I get the detailed procedure to find GCD of 325, 483, 810?

You can find a detailed procedure to find GCD of 325, 483, 810 on our page.

3. How to find GCD of 325, 483, 810 on a calculator?

You can find the GCD of 325, 483, 810 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.