GCD of 384, 857, 336 Calculator

Given Input numbers are 384, 857, 336

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 384

List of positive integer divisors of 384 that divides 384 without a remainder.

1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 64, 96, 128, 192, 384

Divisors of 857

List of positive integer divisors of 857 that divides 857 without a remainder.

1, 857

Divisors of 336

List of positive integer divisors of 336 that divides 336 without a remainder.

1, 2, 3, 4, 6, 7, 8, 12, 14, 16, 21, 24, 28, 42, 48, 56, 84, 112, 168, 336

Greatest Common Divisior

We found the divisors of 384, 857, 336 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 384, 857, 336 is 1.

Therefore, GCD of numbers 384, 857, 336 is 1

Given Input Data is 384, 857, 336

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 384 is 2 x 2 x 2 x 2 x 2 x 2 x 2 x 3

Prime Factorization of 857 is 857

Prime Factorization of 336 is 2 x 2 x 2 x 2 x 3 x 7

The above numbers do not have any common prime factor. So GCD is 1

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(384, 857) = 329088

GCD(384, 857) = ( 384 x 857 ) / 329088

GCD(384, 857) = 329088 / 329088

GCD(384, 857) = 1

Step2:

Here we consider the GCD from the above i.e. 1 as first number and the next as 336

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(1, 336) = 336

GCD(1, 336) = ( 1 x 336 ) / 336

GCD(1, 336) = 336 / 336

GCD(1, 336) = 1

GCD of 384, 857, 336 is 1

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1. What is the GCD of 384, 857, 336?

GCD of 384, 857, 336 is 1

2. Where do I get the detailed procedure to find GCD of 384, 857, 336?

You can find a detailed procedure to find GCD of 384, 857, 336 on our page.

3. How to find GCD of 384, 857, 336 on a calculator?

You can find the GCD of 384, 857, 336 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.