GCD of 408, 560, 259 Calculator

Given Input numbers are 408, 560, 259

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 408

List of positive integer divisors of 408 that divides 408 without a remainder.

1, 2, 3, 4, 6, 8, 12, 17, 24, 34, 51, 68, 102, 136, 204, 408

Divisors of 560

List of positive integer divisors of 560 that divides 560 without a remainder.

1, 2, 4, 5, 7, 8, 10, 14, 16, 20, 28, 35, 40, 56, 70, 80, 112, 140, 280, 560

Divisors of 259

List of positive integer divisors of 259 that divides 259 without a remainder.

1, 7, 37, 259

Greatest Common Divisior

We found the divisors of 408, 560, 259 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 408, 560, 259 is 1.

Therefore, GCD of numbers 408, 560, 259 is 1

Given Input Data is 408, 560, 259

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 408 is 2 x 2 x 2 x 3 x 17

Prime Factorization of 560 is 2 x 2 x 2 x 2 x 5 x 7

Prime Factorization of 259 is 7 x 37

The above numbers do not have any common prime factor. So GCD is 1

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(408, 560) = 28560

GCD(408, 560) = ( 408 x 560 ) / 28560

GCD(408, 560) = 228480 / 28560

GCD(408, 560) = 8

Step2:

Here we consider the GCD from the above i.e. 8 as first number and the next as 259

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(8, 259) = 2072

GCD(8, 259) = ( 8 x 259 ) / 2072

GCD(8, 259) = 2072 / 2072

GCD(8, 259) = 1

GCD of 408, 560, 259 is 1

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1. What is the GCD of 408, 560, 259?

GCD of 408, 560, 259 is 1

2. Where do I get the detailed procedure to find GCD of 408, 560, 259?

You can find a detailed procedure to find GCD of 408, 560, 259 on our page.

3. How to find GCD of 408, 560, 259 on a calculator?

You can find the GCD of 408, 560, 259 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.