Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
Make use of GCD Calculator to determine the Greatest Common Divisor of 428, 471, 542, 127 i.e. 1 largest integer that divides all the numbers equally.
GCD of 428, 471, 542, 127 is 1
GCD(428, 471, 542, 127) = 1
Ex: 10, 15, 20 (or) 24, 48, 96,45 (or) 78902, 89765, 12345
GCD of numbers 428, 471, 542, 127 is 1
GCD(428, 471, 542, 127) = 1
Given Input numbers are 428, 471, 542, 127
To find the GCD of numbers using factoring list out all the divisors of each number
Divisors of 428
List of positive integer divisors of 428 that divides 428 without a remainder.
1, 2, 4, 107, 214, 428
Divisors of 471
List of positive integer divisors of 471 that divides 471 without a remainder.
1, 3, 157, 471
Divisors of 542
List of positive integer divisors of 542 that divides 542 without a remainder.
1, 2, 271, 542
Divisors of 127
List of positive integer divisors of 127 that divides 127 without a remainder.
1, 127
Greatest Common Divisior
We found the divisors of 428, 471, 542, 127 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 428, 471, 542, 127 is 1.
Therefore, GCD of numbers 428, 471, 542, 127 is 1
Given Input Data is 428, 471, 542, 127
Make a list of Prime Factors of all the given numbers initially
Prime Factorization of 428 is 2 x 2 x 107
Prime Factorization of 471 is 3 x 157
Prime Factorization of 542 is 2 x 271
Prime Factorization of 127 is 127
The above numbers do not have any common prime factor. So GCD is 1
Step1:
Let's calculate the GCD of first two numbers
The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)
LCM(428, 471) = 201588
GCD(428, 471) = ( 428 x 471 ) / 201588
GCD(428, 471) = 201588 / 201588
GCD(428, 471) = 1
Step2:
Here we consider the GCD from the above i.e. 1 as first number and the next as 542
The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)
LCM(1, 542) = 542
GCD(1, 542) = ( 1 x 542 ) / 542
GCD(1, 542) = 542 / 542
GCD(1, 542) = 1
Step3:
Here we consider the GCD from the above i.e. 1 as first number and the next as 127
The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)
LCM(1, 127) = 127
GCD(1, 127) = ( 1 x 127 ) / 127
GCD(1, 127) = 127 / 127
GCD(1, 127) = 1
GCD of 428, 471, 542, 127 is 1
Here are some samples of GCD of Numbers calculations.
1. What is the GCD of 428, 471, 542, 127?
GCD of 428, 471, 542, 127 is 1
2. Where do I get the detailed procedure to find GCD of 428, 471, 542, 127?
You can find a detailed procedure to find GCD of 428, 471, 542, 127 on our page.
3. How to find GCD of 428, 471, 542, 127 on a calculator?
You can find the GCD of 428, 471, 542, 127 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.