GCD of 428, 471, 542, 127 Calculator

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023


Make use of GCD Calculator to determine the Greatest Common Divisor of 428, 471, 542, 127 i.e. 1 largest integer that divides all the numbers equally.

GCD of 428, 471, 542, 127 is 1

GCD(428, 471, 542, 127) = 1

Ex: 10, 15, 20 (or) 24, 48, 96,45 (or) 78902, 89765, 12345

GCD of

GCD of numbers 428, 471, 542, 127 is 1

GCD(428, 471, 542, 127) = 1

GCD of 428,471,542,127 Calculator

GCDof 428,471,542,127 is 1

Given Input numbers are 428, 471, 542, 127

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 428

List of positive integer divisors of 428 that divides 428 without a remainder.

1, 2, 4, 107, 214, 428

Divisors of 471

List of positive integer divisors of 471 that divides 471 without a remainder.

1, 3, 157, 471

Divisors of 542

List of positive integer divisors of 542 that divides 542 without a remainder.

1, 2, 271, 542

Divisors of 127

List of positive integer divisors of 127 that divides 127 without a remainder.

1, 127

Greatest Common Divisior

We found the divisors of 428, 471, 542, 127 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 428, 471, 542, 127 is 1.

Therefore, GCD of numbers 428, 471, 542, 127 is 1

Finding GCD of 428, 471, 542, 127 using Prime Factorization

Given Input Data is 428, 471, 542, 127

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 428 is 2 x 2 x 107

Prime Factorization of 471 is 3 x 157

Prime Factorization of 542 is 2 x 271

Prime Factorization of 127 is 127

The above numbers do not have any common prime factor. So GCD is 1

Finding GCD of 428, 471, 542, 127 using LCM Formula

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(428, 471) = 201588

GCD(428, 471) = ( 428 x 471 ) / 201588

GCD(428, 471) = 201588 / 201588

GCD(428, 471) = 1


Step2:

Here we consider the GCD from the above i.e. 1 as first number and the next as 542

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(1, 542) = 542

GCD(1, 542) = ( 1 x 542 ) / 542

GCD(1, 542) = 542 / 542

GCD(1, 542) = 1


Step3:

Here we consider the GCD from the above i.e. 1 as first number and the next as 127

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(1, 127) = 127

GCD(1, 127) = ( 1 x 127 ) / 127

GCD(1, 127) = 127 / 127

GCD(1, 127) = 1

GCD of 428, 471, 542, 127 is 1

GCD of Numbers Calculation Examples

FAQs on GCD of numbers 428, 471, 542, 127

1. What is the GCD of 428, 471, 542, 127?

GCD of 428, 471, 542, 127 is 1


2. Where do I get the detailed procedure to find GCD of 428, 471, 542, 127?

You can find a detailed procedure to find GCD of 428, 471, 542, 127 on our page.


3. How to find GCD of 428, 471, 542, 127 on a calculator?

You can find the GCD of 428, 471, 542, 127 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.