GCD of 434, 113, 489 Calculator

Given Input numbers are 434, 113, 489

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 434

List of positive integer divisors of 434 that divides 434 without a remainder.

1, 2, 7, 14, 31, 62, 217, 434

Divisors of 113

List of positive integer divisors of 113 that divides 113 without a remainder.

1, 113

Divisors of 489

List of positive integer divisors of 489 that divides 489 without a remainder.

1, 3, 163, 489

Greatest Common Divisior

We found the divisors of 434, 113, 489 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 434, 113, 489 is 1.

Therefore, GCD of numbers 434, 113, 489 is 1

Given Input Data is 434, 113, 489

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 434 is 2 x 7 x 31

Prime Factorization of 113 is 113

Prime Factorization of 489 is 3 x 163

The above numbers do not have any common prime factor. So GCD is 1

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(434, 113) = 49042

GCD(434, 113) = ( 434 x 113 ) / 49042

GCD(434, 113) = 49042 / 49042

GCD(434, 113) = 1

Step2:

Here we consider the GCD from the above i.e. 1 as first number and the next as 489

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(1, 489) = 489

GCD(1, 489) = ( 1 x 489 ) / 489

GCD(1, 489) = 489 / 489

GCD(1, 489) = 1

GCD of 434, 113, 489 is 1

Here are some samples of GCD of Numbers calculations.

• GCD of 851, 186, 904
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• GCD of 146, 422, 173
• GCD of 543, 485, 819

1. What is the GCD of 434, 113, 489?

GCD of 434, 113, 489 is 1

2. Where do I get the detailed procedure to find GCD of 434, 113, 489?

You can find a detailed procedure to find GCD of 434, 113, 489 on our page.

3. How to find GCD of 434, 113, 489 on a calculator?

You can find the GCD of 434, 113, 489 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.