GCD of 457, 744, 792 Calculator

Given Input numbers are 457, 744, 792

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 457

List of positive integer divisors of 457 that divides 457 without a remainder.

1, 457

Divisors of 744

List of positive integer divisors of 744 that divides 744 without a remainder.

1, 2, 3, 4, 6, 8, 12, 24, 31, 62, 93, 124, 186, 248, 372, 744

Divisors of 792

List of positive integer divisors of 792 that divides 792 without a remainder.

1, 2, 3, 4, 6, 8, 9, 11, 12, 18, 22, 24, 33, 36, 44, 66, 72, 88, 99, 132, 198, 264, 396, 792

Greatest Common Divisior

We found the divisors of 457, 744, 792 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 457, 744, 792 is 1.

Therefore, GCD of numbers 457, 744, 792 is 1

Given Input Data is 457, 744, 792

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 457 is 457

Prime Factorization of 744 is 2 x 2 x 2 x 3 x 31

Prime Factorization of 792 is 2 x 2 x 2 x 3 x 3 x 11

The above numbers do not have any common prime factor. So GCD is 1

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(457, 744) = 340008

GCD(457, 744) = ( 457 x 744 ) / 340008

GCD(457, 744) = 340008 / 340008

GCD(457, 744) = 1

Step2:

Here we consider the GCD from the above i.e. 1 as first number and the next as 792

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(1, 792) = 792

GCD(1, 792) = ( 1 x 792 ) / 792

GCD(1, 792) = 792 / 792

GCD(1, 792) = 1

GCD of 457, 744, 792 is 1

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1. What is the GCD of 457, 744, 792?

GCD of 457, 744, 792 is 1

2. Where do I get the detailed procedure to find GCD of 457, 744, 792?

You can find a detailed procedure to find GCD of 457, 744, 792 on our page.

3. How to find GCD of 457, 744, 792 on a calculator?

You can find the GCD of 457, 744, 792 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.