GCD of 518, 481, 533 Calculator

Given Input numbers are 518, 481, 533

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 518

List of positive integer divisors of 518 that divides 518 without a remainder.

1, 2, 7, 14, 37, 74, 259, 518

Divisors of 481

List of positive integer divisors of 481 that divides 481 without a remainder.

1, 13, 37, 481

Divisors of 533

List of positive integer divisors of 533 that divides 533 without a remainder.

1, 13, 41, 533

Greatest Common Divisior

We found the divisors of 518, 481, 533 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 518, 481, 533 is 1.

Therefore, GCD of numbers 518, 481, 533 is 1

Given Input Data is 518, 481, 533

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 518 is 2 x 7 x 37

Prime Factorization of 481 is 13 x 37

Prime Factorization of 533 is 13 x 41

The above numbers do not have any common prime factor. So GCD is 1

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(518, 481) = 6734

GCD(518, 481) = ( 518 x 481 ) / 6734

GCD(518, 481) = 249158 / 6734

GCD(518, 481) = 37

Step2:

Here we consider the GCD from the above i.e. 37 as first number and the next as 533

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(37, 533) = 19721

GCD(37, 533) = ( 37 x 533 ) / 19721

GCD(37, 533) = 19721 / 19721

GCD(37, 533) = 1

GCD of 518, 481, 533 is 1

Here are some samples of GCD of Numbers calculations.

• GCD of 870, 694, 922
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• GCD of 499, 662, 260

1. What is the GCD of 518, 481, 533?

GCD of 518, 481, 533 is 1

2. Where do I get the detailed procedure to find GCD of 518, 481, 533?

You can find a detailed procedure to find GCD of 518, 481, 533 on our page.

3. How to find GCD of 518, 481, 533 on a calculator?

You can find the GCD of 518, 481, 533 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.