GCD of 536, 810, 16 Calculator

Given Input numbers are 536, 810, 16

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 536

List of positive integer divisors of 536 that divides 536 without a remainder.

1, 2, 4, 8, 67, 134, 268, 536

Divisors of 810

List of positive integer divisors of 810 that divides 810 without a remainder.

1, 2, 3, 5, 6, 9, 10, 15, 18, 27, 30, 45, 54, 81, 90, 135, 162, 270, 405, 810

Divisors of 16

List of positive integer divisors of 16 that divides 16 without a remainder.

1, 2, 4, 8, 16

Greatest Common Divisior

We found the divisors of 536, 810, 16 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 536, 810, 16 is 2.

Therefore, GCD of numbers 536, 810, 16 is 2

Given Input Data is 536, 810, 16

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 536 is 2 x 2 x 2 x 67

Prime Factorization of 810 is 2 x 3 x 3 x 3 x 3 x 5

Prime Factorization of 16 is 2 x 2 x 2 x 2

Highest common occurrences in the given inputs are 2¹

Multiplying them we get the GCD as 2

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(536, 810) = 217080

GCD(536, 810) = ( 536 x 810 ) / 217080

GCD(536, 810) = 434160 / 217080

GCD(536, 810) = 2

Step2:

Here we consider the GCD from the above i.e. 2 as first number and the next as 16

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(2, 16) = 16

GCD(2, 16) = ( 2 x 16 ) / 16

GCD(2, 16) = 32 / 16

GCD(2, 16) = 2

GCD of 536, 810, 16 is 2

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• GCD of 583, 840, 54
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1. What is the GCD of 536, 810, 16?

GCD of 536, 810, 16 is 2

2. Where do I get the detailed procedure to find GCD of 536, 810, 16?

You can find a detailed procedure to find GCD of 536, 810, 16 on our page.

3. How to find GCD of 536, 810, 16 on a calculator?

You can find the GCD of 536, 810, 16 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.