GCD of 595, 352, 580 Calculator

Given Input numbers are 595, 352, 580

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 595

List of positive integer divisors of 595 that divides 595 without a remainder.

1, 5, 7, 17, 35, 85, 119, 595

Divisors of 352

List of positive integer divisors of 352 that divides 352 without a remainder.

1, 2, 4, 8, 11, 16, 22, 32, 44, 88, 176, 352

Divisors of 580

List of positive integer divisors of 580 that divides 580 without a remainder.

1, 2, 4, 5, 10, 20, 29, 58, 116, 145, 290, 580

Greatest Common Divisior

We found the divisors of 595, 352, 580 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 595, 352, 580 is 1.

Therefore, GCD of numbers 595, 352, 580 is 1

Given Input Data is 595, 352, 580

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 595 is 5 x 7 x 17

Prime Factorization of 352 is 2 x 2 x 2 x 2 x 2 x 11

Prime Factorization of 580 is 2 x 2 x 5 x 29

The above numbers do not have any common prime factor. So GCD is 1

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(595, 352) = 209440

GCD(595, 352) = ( 595 x 352 ) / 209440

GCD(595, 352) = 209440 / 209440

GCD(595, 352) = 1

Step2:

Here we consider the GCD from the above i.e. 1 as first number and the next as 580

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(1, 580) = 580

GCD(1, 580) = ( 1 x 580 ) / 580

GCD(1, 580) = 580 / 580

GCD(1, 580) = 1

GCD of 595, 352, 580 is 1

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• GCD of 975, 564, 316
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1. What is the GCD of 595, 352, 580?

GCD of 595, 352, 580 is 1

2. Where do I get the detailed procedure to find GCD of 595, 352, 580?

You can find a detailed procedure to find GCD of 595, 352, 580 on our page.

3. How to find GCD of 595, 352, 580 on a calculator?

You can find the GCD of 595, 352, 580 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.