GCD of 628, 239, 497 Calculator

Given Input numbers are 628, 239, 497

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 628

List of positive integer divisors of 628 that divides 628 without a remainder.

1, 2, 4, 157, 314, 628

Divisors of 239

List of positive integer divisors of 239 that divides 239 without a remainder.

1, 239

Divisors of 497

List of positive integer divisors of 497 that divides 497 without a remainder.

1, 7, 71, 497

Greatest Common Divisior

We found the divisors of 628, 239, 497 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 628, 239, 497 is 1.

Therefore, GCD of numbers 628, 239, 497 is 1

Given Input Data is 628, 239, 497

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 628 is 2 x 2 x 157

Prime Factorization of 239 is 239

Prime Factorization of 497 is 7 x 71

The above numbers do not have any common prime factor. So GCD is 1

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(628, 239) = 150092

GCD(628, 239) = ( 628 x 239 ) / 150092

GCD(628, 239) = 150092 / 150092

GCD(628, 239) = 1

Step2:

Here we consider the GCD from the above i.e. 1 as first number and the next as 497

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(1, 497) = 497

GCD(1, 497) = ( 1 x 497 ) / 497

GCD(1, 497) = 497 / 497

GCD(1, 497) = 1

GCD of 628, 239, 497 is 1

Here are some samples of GCD of Numbers calculations.

• GCD of 232, 121, 474
• GCD of 970, 968, 452
• GCD of 311, 220, 354
• GCD of 937, 903, 562
• GCD of 932, 839, 715

1. What is the GCD of 628, 239, 497?

GCD of 628, 239, 497 is 1

2. Where do I get the detailed procedure to find GCD of 628, 239, 497?

You can find a detailed procedure to find GCD of 628, 239, 497 on our page.

3. How to find GCD of 628, 239, 497 on a calculator?

You can find the GCD of 628, 239, 497 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.