GCD of 648, 133, 570 Calculator

Given Input numbers are 648, 133, 570

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 648

List of positive integer divisors of 648 that divides 648 without a remainder.

1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 27, 36, 54, 72, 81, 108, 162, 216, 324, 648

Divisors of 133

List of positive integer divisors of 133 that divides 133 without a remainder.

1, 7, 19, 133

Divisors of 570

List of positive integer divisors of 570 that divides 570 without a remainder.

1, 2, 3, 5, 6, 10, 15, 19, 30, 38, 57, 95, 114, 190, 285, 570

Greatest Common Divisior

We found the divisors of 648, 133, 570 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 648, 133, 570 is 1.

Therefore, GCD of numbers 648, 133, 570 is 1

Given Input Data is 648, 133, 570

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 648 is 2 x 2 x 2 x 3 x 3 x 3 x 3

Prime Factorization of 133 is 7 x 19

Prime Factorization of 570 is 2 x 3 x 5 x 19

The above numbers do not have any common prime factor. So GCD is 1

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(648, 133) = 86184

GCD(648, 133) = ( 648 x 133 ) / 86184

GCD(648, 133) = 86184 / 86184

GCD(648, 133) = 1

Step2:

Here we consider the GCD from the above i.e. 1 as first number and the next as 570

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(1, 570) = 570

GCD(1, 570) = ( 1 x 570 ) / 570

GCD(1, 570) = 570 / 570

GCD(1, 570) = 1

GCD of 648, 133, 570 is 1

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1. What is the GCD of 648, 133, 570?

GCD of 648, 133, 570 is 1

2. Where do I get the detailed procedure to find GCD of 648, 133, 570?

You can find a detailed procedure to find GCD of 648, 133, 570 on our page.

3. How to find GCD of 648, 133, 570 on a calculator?

You can find the GCD of 648, 133, 570 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.