GCD of 725, 652, 47, 430 Calculator

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023


Make use of GCD Calculator to determine the Greatest Common Divisor of 725, 652, 47, 430 i.e. 1 largest integer that divides all the numbers equally.

GCD of 725, 652, 47, 430 is 1

GCD(725, 652, 47, 430) = 1

Ex: 10, 15, 20 (or) 24, 48, 96,45 (or) 78902, 89765, 12345

GCD of

GCD of numbers 725, 652, 47, 430 is 1

GCD(725, 652, 47, 430) = 1

GCD of 725,652,47,430 Calculator

GCDof 725,652,47,430 is 1

Given Input numbers are 725, 652, 47, 430

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 725

List of positive integer divisors of 725 that divides 725 without a remainder.

1, 5, 25, 29, 145, 725

Divisors of 652

List of positive integer divisors of 652 that divides 652 without a remainder.

1, 2, 4, 163, 326, 652

Divisors of 47

List of positive integer divisors of 47 that divides 47 without a remainder.

1, 47

Divisors of 430

List of positive integer divisors of 430 that divides 430 without a remainder.

1, 2, 5, 10, 43, 86, 215, 430

Greatest Common Divisior

We found the divisors of 725, 652, 47, 430 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 725, 652, 47, 430 is 1.

Therefore, GCD of numbers 725, 652, 47, 430 is 1

Finding GCD of 725, 652, 47, 430 using Prime Factorization

Given Input Data is 725, 652, 47, 430

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 725 is 5 x 5 x 29

Prime Factorization of 652 is 2 x 2 x 163

Prime Factorization of 47 is 47

Prime Factorization of 430 is 2 x 5 x 43

The above numbers do not have any common prime factor. So GCD is 1

Finding GCD of 725, 652, 47, 430 using LCM Formula

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(725, 652) = 472700

GCD(725, 652) = ( 725 x 652 ) / 472700

GCD(725, 652) = 472700 / 472700

GCD(725, 652) = 1


Step2:

Here we consider the GCD from the above i.e. 1 as first number and the next as 47

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(1, 47) = 47

GCD(1, 47) = ( 1 x 47 ) / 47

GCD(1, 47) = 47 / 47

GCD(1, 47) = 1


Step3:

Here we consider the GCD from the above i.e. 1 as first number and the next as 430

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(1, 430) = 430

GCD(1, 430) = ( 1 x 430 ) / 430

GCD(1, 430) = 430 / 430

GCD(1, 430) = 1

GCD of 725, 652, 47, 430 is 1

GCD of Numbers Calculation Examples

FAQs on GCD of numbers 725, 652, 47, 430

1. What is the GCD of 725, 652, 47, 430?

GCD of 725, 652, 47, 430 is 1


2. Where do I get the detailed procedure to find GCD of 725, 652, 47, 430?

You can find a detailed procedure to find GCD of 725, 652, 47, 430 on our page.


3. How to find GCD of 725, 652, 47, 430 on a calculator?

You can find the GCD of 725, 652, 47, 430 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.