GCD of 825, 483, 690 Calculator

Given Input numbers are 825, 483, 690

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 825

List of positive integer divisors of 825 that divides 825 without a remainder.

1, 3, 5, 11, 15, 25, 33, 55, 75, 165, 275, 825

Divisors of 483

List of positive integer divisors of 483 that divides 483 without a remainder.

1, 3, 7, 21, 23, 69, 161, 483

Divisors of 690

List of positive integer divisors of 690 that divides 690 without a remainder.

1, 2, 3, 5, 6, 10, 15, 23, 30, 46, 69, 115, 138, 230, 345, 690

Greatest Common Divisior

We found the divisors of 825, 483, 690 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 825, 483, 690 is 3.

Therefore, GCD of numbers 825, 483, 690 is 3

Given Input Data is 825, 483, 690

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 825 is 3 x 5 x 5 x 11

Prime Factorization of 483 is 3 x 7 x 23

Prime Factorization of 690 is 2 x 3 x 5 x 23

Highest common occurrences in the given inputs are 3¹

Multiplying them we get the GCD as 3

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(825, 483) = 132825

GCD(825, 483) = ( 825 x 483 ) / 132825

GCD(825, 483) = 398475 / 132825

GCD(825, 483) = 3

Step2:

Here we consider the GCD from the above i.e. 3 as first number and the next as 690

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(3, 690) = 690

GCD(3, 690) = ( 3 x 690 ) / 690

GCD(3, 690) = 2070 / 690

GCD(3, 690) = 3

GCD of 825, 483, 690 is 3

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1. What is the GCD of 825, 483, 690?

GCD of 825, 483, 690 is 3

2. Where do I get the detailed procedure to find GCD of 825, 483, 690?

You can find a detailed procedure to find GCD of 825, 483, 690 on our page.

3. How to find GCD of 825, 483, 690 on a calculator?

You can find the GCD of 825, 483, 690 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.