GCD of 828, 896, 449 Calculator

Given Input numbers are 828, 896, 449

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 828

List of positive integer divisors of 828 that divides 828 without a remainder.

1, 2, 3, 4, 6, 9, 12, 18, 23, 36, 46, 69, 92, 138, 207, 276, 414, 828

Divisors of 896

List of positive integer divisors of 896 that divides 896 without a remainder.

1, 2, 4, 7, 8, 14, 16, 28, 32, 56, 64, 112, 128, 224, 448, 896

Divisors of 449

List of positive integer divisors of 449 that divides 449 without a remainder.

1, 449

Greatest Common Divisior

We found the divisors of 828, 896, 449 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 828, 896, 449 is 1.

Therefore, GCD of numbers 828, 896, 449 is 1

Given Input Data is 828, 896, 449

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 828 is 2 x 2 x 3 x 3 x 23

Prime Factorization of 896 is 2 x 2 x 2 x 2 x 2 x 2 x 2 x 7

Prime Factorization of 449 is 449

The above numbers do not have any common prime factor. So GCD is 1

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(828, 896) = 185472

GCD(828, 896) = ( 828 x 896 ) / 185472

GCD(828, 896) = 741888 / 185472

GCD(828, 896) = 4

Step2:

Here we consider the GCD from the above i.e. 4 as first number and the next as 449

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(4, 449) = 1796

GCD(4, 449) = ( 4 x 449 ) / 1796

GCD(4, 449) = 1796 / 1796

GCD(4, 449) = 1

GCD of 828, 896, 449 is 1

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1. What is the GCD of 828, 896, 449?

GCD of 828, 896, 449 is 1

2. Where do I get the detailed procedure to find GCD of 828, 896, 449?

You can find a detailed procedure to find GCD of 828, 896, 449 on our page.

3. How to find GCD of 828, 896, 449 on a calculator?

You can find the GCD of 828, 896, 449 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.