GCD of 880, 715, 266 Calculator

Given Input numbers are 880, 715, 266

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 880

List of positive integer divisors of 880 that divides 880 without a remainder.

1, 2, 4, 5, 8, 10, 11, 16, 20, 22, 40, 44, 55, 80, 88, 110, 176, 220, 440, 880

Divisors of 715

List of positive integer divisors of 715 that divides 715 without a remainder.

1, 5, 11, 13, 55, 65, 143, 715

Divisors of 266

List of positive integer divisors of 266 that divides 266 without a remainder.

1, 2, 7, 14, 19, 38, 133, 266

Greatest Common Divisior

We found the divisors of 880, 715, 266 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 880, 715, 266 is 1.

Therefore, GCD of numbers 880, 715, 266 is 1

Given Input Data is 880, 715, 266

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 880 is 2 x 2 x 2 x 2 x 5 x 11

Prime Factorization of 715 is 5 x 11 x 13

Prime Factorization of 266 is 2 x 7 x 19

The above numbers do not have any common prime factor. So GCD is 1

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(880, 715) = 11440

GCD(880, 715) = ( 880 x 715 ) / 11440

GCD(880, 715) = 629200 / 11440

GCD(880, 715) = 55

Step2:

Here we consider the GCD from the above i.e. 55 as first number and the next as 266

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(55, 266) = 14630

GCD(55, 266) = ( 55 x 266 ) / 14630

GCD(55, 266) = 14630 / 14630

GCD(55, 266) = 1

GCD of 880, 715, 266 is 1

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1. What is the GCD of 880, 715, 266?

GCD of 880, 715, 266 is 1

2. Where do I get the detailed procedure to find GCD of 880, 715, 266?

You can find a detailed procedure to find GCD of 880, 715, 266 on our page.

3. How to find GCD of 880, 715, 266 on a calculator?

You can find the GCD of 880, 715, 266 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.