GCD of 882, 615, 915 Calculator

Given Input numbers are 882, 615, 915

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 882

List of positive integer divisors of 882 that divides 882 without a remainder.

1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 49, 63, 98, 126, 147, 294, 441, 882

Divisors of 615

List of positive integer divisors of 615 that divides 615 without a remainder.

1, 3, 5, 15, 41, 123, 205, 615

Divisors of 915

List of positive integer divisors of 915 that divides 915 without a remainder.

1, 3, 5, 15, 61, 183, 305, 915

Greatest Common Divisior

We found the divisors of 882, 615, 915 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 882, 615, 915 is 3.

Therefore, GCD of numbers 882, 615, 915 is 3

Given Input Data is 882, 615, 915

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 882 is 2 x 3 x 3 x 7 x 7

Prime Factorization of 615 is 3 x 5 x 41

Prime Factorization of 915 is 3 x 5 x 61

Highest common occurrences in the given inputs are 3¹

Multiplying them we get the GCD as 3

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(882, 615) = 180810

GCD(882, 615) = ( 882 x 615 ) / 180810

GCD(882, 615) = 542430 / 180810

GCD(882, 615) = 3

Step2:

Here we consider the GCD from the above i.e. 3 as first number and the next as 915

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(3, 915) = 915

GCD(3, 915) = ( 3 x 915 ) / 915

GCD(3, 915) = 2745 / 915

GCD(3, 915) = 3

GCD of 882, 615, 915 is 3

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1. What is the GCD of 882, 615, 915?

GCD of 882, 615, 915 is 3

2. Where do I get the detailed procedure to find GCD of 882, 615, 915?

You can find a detailed procedure to find GCD of 882, 615, 915 on our page.

3. How to find GCD of 882, 615, 915 on a calculator?

You can find the GCD of 882, 615, 915 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.