GCD of 920, 688, 530 Calculator

Given Input numbers are 920, 688, 530

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 920

List of positive integer divisors of 920 that divides 920 without a remainder.

1, 2, 4, 5, 8, 10, 20, 23, 40, 46, 92, 115, 184, 230, 460, 920

Divisors of 688

List of positive integer divisors of 688 that divides 688 without a remainder.

1, 2, 4, 8, 16, 43, 86, 172, 344, 688

Divisors of 530

List of positive integer divisors of 530 that divides 530 without a remainder.

1, 2, 5, 10, 53, 106, 265, 530

Greatest Common Divisior

We found the divisors of 920, 688, 530 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 920, 688, 530 is 2.

Therefore, GCD of numbers 920, 688, 530 is 2

Given Input Data is 920, 688, 530

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 920 is 2 x 2 x 2 x 5 x 23

Prime Factorization of 688 is 2 x 2 x 2 x 2 x 43

Prime Factorization of 530 is 2 x 5 x 53

Highest common occurrences in the given inputs are 2¹

Multiplying them we get the GCD as 2

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(920, 688) = 79120

GCD(920, 688) = ( 920 x 688 ) / 79120

GCD(920, 688) = 632960 / 79120

GCD(920, 688) = 8

Step2:

Here we consider the GCD from the above i.e. 8 as first number and the next as 530

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(8, 530) = 2120

GCD(8, 530) = ( 8 x 530 ) / 2120

GCD(8, 530) = 4240 / 2120

GCD(8, 530) = 2

GCD of 920, 688, 530 is 2

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1. What is the GCD of 920, 688, 530?

GCD of 920, 688, 530 is 2

2. Where do I get the detailed procedure to find GCD of 920, 688, 530?

You can find a detailed procedure to find GCD of 920, 688, 530 on our page.

3. How to find GCD of 920, 688, 530 on a calculator?

You can find the GCD of 920, 688, 530 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.