Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
Make use of GCD Calculator to determine the Greatest Common Divisor of 96, 492, 712, 530 i.e. 2 largest integer that divides all the numbers equally.
GCD of 96, 492, 712, 530 is 2
GCD(96, 492, 712, 530) = 2
Ex: 10, 15, 20 (or) 24, 48, 96,45 (or) 78902, 89765, 12345
GCD of numbers 96, 492, 712, 530 is 2
GCD(96, 492, 712, 530) = 2
Given Input numbers are 96, 492, 712, 530
To find the GCD of numbers using factoring list out all the divisors of each number
Divisors of 96
List of positive integer divisors of 96 that divides 96 without a remainder.
1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96
Divisors of 492
List of positive integer divisors of 492 that divides 492 without a remainder.
1, 2, 3, 4, 6, 12, 41, 82, 123, 164, 246, 492
Divisors of 712
List of positive integer divisors of 712 that divides 712 without a remainder.
1, 2, 4, 8, 89, 178, 356, 712
Divisors of 530
List of positive integer divisors of 530 that divides 530 without a remainder.
1, 2, 5, 10, 53, 106, 265, 530
Greatest Common Divisior
We found the divisors of 96, 492, 712, 530 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 96, 492, 712, 530 is 2.
Therefore, GCD of numbers 96, 492, 712, 530 is 2
Given Input Data is 96, 492, 712, 530
Make a list of Prime Factors of all the given numbers initially
Prime Factorization of 96 is 2 x 2 x 2 x 2 x 2 x 3
Prime Factorization of 492 is 2 x 2 x 3 x 41
Prime Factorization of 712 is 2 x 2 x 2 x 89
Prime Factorization of 530 is 2 x 5 x 53
Highest common occurrences in the given inputs are 21
Multiplying them we get the GCD as 2
Step1:
Let's calculate the GCD of first two numbers
The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)
LCM(96, 492) = 3936
GCD(96, 492) = ( 96 x 492 ) / 3936
GCD(96, 492) = 47232 / 3936
GCD(96, 492) = 12
Step2:
Here we consider the GCD from the above i.e. 12 as first number and the next as 712
The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)
LCM(12, 712) = 2136
GCD(12, 712) = ( 12 x 712 ) / 2136
GCD(12, 712) = 8544 / 2136
GCD(12, 712) = 4
Step3:
Here we consider the GCD from the above i.e. 4 as first number and the next as 530
The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)
LCM(4, 530) = 1060
GCD(4, 530) = ( 4 x 530 ) / 1060
GCD(4, 530) = 2120 / 1060
GCD(4, 530) = 2
GCD of 96, 492, 712, 530 is 2
Here are some samples of GCD of Numbers calculations.
1. What is the GCD of 96, 492, 712, 530?
GCD of 96, 492, 712, 530 is 2
2. Where do I get the detailed procedure to find GCD of 96, 492, 712, 530?
You can find a detailed procedure to find GCD of 96, 492, 712, 530 on our page.
3. How to find GCD of 96, 492, 712, 530 on a calculator?
You can find the GCD of 96, 492, 712, 530 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.