Highest Common Factor of 110, 462, 258, 601 using Euclid's algorithm

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023


HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 110, 462, 258, 601 i.e. 1 the largest integer that leaves a remainder zero for all numbers.

HCF of 110, 462, 258, 601 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 110, 462, 258, 601 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 110, 462, 258, 601 is 1.

HCF(110, 462, 258, 601) = 1

HCF of 110, 462, 258, 601 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 110, 462, 258, 601 is 1.

Highest Common Factor of 110,462,258,601 using Euclid's algorithm

Highest Common Factor of 110,462,258,601 is 1

Step 1: Since 462 > 110, we apply the division lemma to 462 and 110, to get

462 = 110 x 4 + 22

Step 2: Since the reminder 110 ≠ 0, we apply division lemma to 22 and 110, to get

110 = 22 x 5 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 22, the HCF of 110 and 462 is 22

Notice that 22 = HCF(110,22) = HCF(462,110) .


We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 258 > 22, we apply the division lemma to 258 and 22, to get

258 = 22 x 11 + 16

Step 2: Since the reminder 22 ≠ 0, we apply division lemma to 16 and 22, to get

22 = 16 x 1 + 6

Step 3: We consider the new divisor 16 and the new remainder 6, and apply the division lemma to get

16 = 6 x 2 + 4

We consider the new divisor 6 and the new remainder 4,and apply the division lemma to get

6 = 4 x 1 + 2

We consider the new divisor 4 and the new remainder 2,and apply the division lemma to get

4 = 2 x 2 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 2, the HCF of 22 and 258 is 2

Notice that 2 = HCF(4,2) = HCF(6,4) = HCF(16,6) = HCF(22,16) = HCF(258,22) .


We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma

Step 1: Since 601 > 2, we apply the division lemma to 601 and 2, to get

601 = 2 x 300 + 1

Step 2: Since the reminder 2 ≠ 0, we apply division lemma to 1 and 2, to get

2 = 1 x 2 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 2 and 601 is 1

Notice that 1 = HCF(2,1) = HCF(601,2) .

HCF using Euclid's Algorithm Calculation Examples

Frequently Asked Questions on HCF of 110, 462, 258, 601 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 110, 462, 258, 601?

Answer: HCF of 110, 462, 258, 601 is 1 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 110, 462, 258, 601 using Euclid's Algorithm?

Answer: For arbitrary numbers 110, 462, 258, 601 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.