Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 112, 723 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 112, 723 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 112, 723 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 112, 723 is 1.
HCF(112, 723) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 112, 723 is 1.
Step 1: Since 723 > 112, we apply the division lemma to 723 and 112, to get
723 = 112 x 6 + 51
Step 2: Since the reminder 112 ≠ 0, we apply division lemma to 51 and 112, to get
112 = 51 x 2 + 10
Step 3: We consider the new divisor 51 and the new remainder 10, and apply the division lemma to get
51 = 10 x 5 + 1
We consider the new divisor 10 and the new remainder 1, and apply the division lemma to get
10 = 1 x 10 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 112 and 723 is 1
Notice that 1 = HCF(10,1) = HCF(51,10) = HCF(112,51) = HCF(723,112) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 112, 723?
Answer: HCF of 112, 723 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 112, 723 using Euclid's Algorithm?
Answer: For arbitrary numbers 112, 723 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.