Highest Common Factor of 1155, 4167, 32447 using Euclid's algorithm
Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 1155, 4167, 32447 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 1155, 4167, 32447 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 1155, 4167, 32447 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 1155, 4167, 32447 is 1.
HCF(1155, 4167, 32447) = 1
HCF of 1155, 4167, 32447 using Euclid's algorithm
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 1155, 4167, 32447 is 1.
Highest Common Factor of 1155,4167,32447 is 1
Step 1: Since 4167 > 1155, we apply the division lemma to 4167 and 1155, to get
4167 = 1155 x 3 + 702
Step 2: Since the reminder 1155 ≠ 0, we apply division lemma to 702 and 1155, to get
1155 = 702 x 1 + 453
Step 3: We consider the new divisor 702 and the new remainder 453, and apply the division lemma to get
702 = 453 x 1 + 249
We consider the new divisor 453 and the new remainder 249,and apply the division lemma to get
453 = 249 x 1 + 204
We consider the new divisor 249 and the new remainder 204,and apply the division lemma to get
249 = 204 x 1 + 45
We consider the new divisor 204 and the new remainder 45,and apply the division lemma to get
204 = 45 x 4 + 24
We consider the new divisor 45 and the new remainder 24,and apply the division lemma to get
45 = 24 x 1 + 21
We consider the new divisor 24 and the new remainder 21,and apply the division lemma to get
24 = 21 x 1 + 3
We consider the new divisor 21 and the new remainder 3,and apply the division lemma to get
21 = 3 x 7 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 3, the HCF of 1155 and 4167 is 3
Notice that 3 = HCF(21,3) = HCF(24,21) = HCF(45,24) = HCF(204,45) = HCF(249,204) = HCF(453,249) = HCF(702,453) = HCF(1155,702) = HCF(4167,1155) .
We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma
Step 1: Since 32447 > 3, we apply the division lemma to 32447 and 3, to get
32447 = 3 x 10815 + 2
Step 2: Since the reminder 3 ≠ 0, we apply division lemma to 2 and 3, to get
3 = 2 x 1 + 1
Step 3: We consider the new divisor 2 and the new remainder 1, and apply the division lemma to get
2 = 1 x 2 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 3 and 32447 is 1
Notice that 1 = HCF(2,1) = HCF(3,2) = HCF(32447,3) .
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Frequently Asked Questions on HCF of 1155, 4167, 32447 using Euclid's Algorithm
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 1155, 4167, 32447?
Answer: HCF of 1155, 4167, 32447 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 1155, 4167, 32447 using Euclid's Algorithm?
Answer: For arbitrary numbers 1155, 4167, 32447 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.