Highest Common Factor of 136, 8500 using Euclid's algorithm

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023


HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 136, 8500 i.e. 68 the largest integer that leaves a remainder zero for all numbers.

HCF of 136, 8500 is 68 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 136, 8500 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 136, 8500 is 68.

HCF(136, 8500) = 68

HCF of 136, 8500 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 136, 8500 is 68.

Highest Common Factor of 136,8500 using Euclid's algorithm

Highest Common Factor of 136,8500 is 68

Step 1: Since 8500 > 136, we apply the division lemma to 8500 and 136, to get

8500 = 136 x 62 + 68

Step 2: Since the reminder 136 ≠ 0, we apply division lemma to 68 and 136, to get

136 = 68 x 2 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 68, the HCF of 136 and 8500 is 68

Notice that 68 = HCF(136,68) = HCF(8500,136) .

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Frequently Asked Questions on HCF of 136, 8500 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 136, 8500?

Answer: HCF of 136, 8500 is 68 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 136, 8500 using Euclid's Algorithm?

Answer: For arbitrary numbers 136, 8500 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.