Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 148, 2270 i.e. 2 the largest integer that leaves a remainder zero for all numbers.
HCF of 148, 2270 is 2 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 148, 2270 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 148, 2270 is 2.
HCF(148, 2270) = 2
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 148, 2270 is 2.
Step 1: Since 2270 > 148, we apply the division lemma to 2270 and 148, to get
2270 = 148 x 15 + 50
Step 2: Since the reminder 148 ≠ 0, we apply division lemma to 50 and 148, to get
148 = 50 x 2 + 48
Step 3: We consider the new divisor 50 and the new remainder 48, and apply the division lemma to get
50 = 48 x 1 + 2
We consider the new divisor 48 and the new remainder 2, and apply the division lemma to get
48 = 2 x 24 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 2, the HCF of 148 and 2270 is 2
Notice that 2 = HCF(48,2) = HCF(50,48) = HCF(148,50) = HCF(2270,148) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 148, 2270?
Answer: HCF of 148, 2270 is 2 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 148, 2270 using Euclid's Algorithm?
Answer: For arbitrary numbers 148, 2270 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.