Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 155, 558 i.e. 31 the largest integer that leaves a remainder zero for all numbers.
HCF of 155, 558 is 31 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 155, 558 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 155, 558 is 31.
HCF(155, 558) = 31
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 155, 558 is 31.
Step 1: Since 558 > 155, we apply the division lemma to 558 and 155, to get
558 = 155 x 3 + 93
Step 2: Since the reminder 155 ≠ 0, we apply division lemma to 93 and 155, to get
155 = 93 x 1 + 62
Step 3: We consider the new divisor 93 and the new remainder 62, and apply the division lemma to get
93 = 62 x 1 + 31
We consider the new divisor 62 and the new remainder 31, and apply the division lemma to get
62 = 31 x 2 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 31, the HCF of 155 and 558 is 31
Notice that 31 = HCF(62,31) = HCF(93,62) = HCF(155,93) = HCF(558,155) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 155, 558?
Answer: HCF of 155, 558 is 31 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 155, 558 using Euclid's Algorithm?
Answer: For arbitrary numbers 155, 558 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.