Highest Common Factor of 171, 513, 647, 54 using Euclid's algorithm
Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 171, 513, 647, 54 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 171, 513, 647, 54 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 171, 513, 647, 54 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 171, 513, 647, 54 is 1.
HCF(171, 513, 647, 54) = 1
HCF of 171, 513, 647, 54 using Euclid's algorithm
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 171, 513, 647, 54 is 1.
Highest Common Factor of 171,513,647,54 is 1
Step 1: Since 513 > 171, we apply the division lemma to 513 and 171, to get
513 = 171 x 3 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 171, the HCF of 171 and 513 is 171
Notice that 171 = HCF(513,171) .
We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma
Step 1: Since 647 > 171, we apply the division lemma to 647 and 171, to get
647 = 171 x 3 + 134
Step 2: Since the reminder 171 ≠ 0, we apply division lemma to 134 and 171, to get
171 = 134 x 1 + 37
Step 3: We consider the new divisor 134 and the new remainder 37, and apply the division lemma to get
134 = 37 x 3 + 23
We consider the new divisor 37 and the new remainder 23,and apply the division lemma to get
37 = 23 x 1 + 14
We consider the new divisor 23 and the new remainder 14,and apply the division lemma to get
23 = 14 x 1 + 9
We consider the new divisor 14 and the new remainder 9,and apply the division lemma to get
14 = 9 x 1 + 5
We consider the new divisor 9 and the new remainder 5,and apply the division lemma to get
9 = 5 x 1 + 4
We consider the new divisor 5 and the new remainder 4,and apply the division lemma to get
5 = 4 x 1 + 1
We consider the new divisor 4 and the new remainder 1,and apply the division lemma to get
4 = 1 x 4 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 171 and 647 is 1
Notice that 1 = HCF(4,1) = HCF(5,4) = HCF(9,5) = HCF(14,9) = HCF(23,14) = HCF(37,23) = HCF(134,37) = HCF(171,134) = HCF(647,171) .
We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma
Step 1: Since 54 > 1, we apply the division lemma to 54 and 1, to get
54 = 1 x 54 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 54 is 1
Notice that 1 = HCF(54,1) .
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Frequently Asked Questions on HCF of 171, 513, 647, 54 using Euclid's Algorithm
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 171, 513, 647, 54?
Answer: HCF of 171, 513, 647, 54 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 171, 513, 647, 54 using Euclid's Algorithm?
Answer: For arbitrary numbers 171, 513, 647, 54 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.