Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 248, 815 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 248, 815 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 248, 815 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 248, 815 is 1.
HCF(248, 815) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 248, 815 is 1.
Step 1: Since 815 > 248, we apply the division lemma to 815 and 248, to get
815 = 248 x 3 + 71
Step 2: Since the reminder 248 ≠ 0, we apply division lemma to 71 and 248, to get
248 = 71 x 3 + 35
Step 3: We consider the new divisor 71 and the new remainder 35, and apply the division lemma to get
71 = 35 x 2 + 1
We consider the new divisor 35 and the new remainder 1, and apply the division lemma to get
35 = 1 x 35 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 248 and 815 is 1
Notice that 1 = HCF(35,1) = HCF(71,35) = HCF(248,71) = HCF(815,248) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 248, 815?
Answer: HCF of 248, 815 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 248, 815 using Euclid's Algorithm?
Answer: For arbitrary numbers 248, 815 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.