Highest Common Factor of 2502, 1448, 82731 using Euclid's algorithm
Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 2502, 1448, 82731 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 2502, 1448, 82731 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 2502, 1448, 82731 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 2502, 1448, 82731 is 1.
HCF(2502, 1448, 82731) = 1
HCF of 2502, 1448, 82731 using Euclid's algorithm
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 2502, 1448, 82731 is 1.
Highest Common Factor of 2502,1448,82731 is 1
Step 1: Since 2502 > 1448, we apply the division lemma to 2502 and 1448, to get
2502 = 1448 x 1 + 1054
Step 2: Since the reminder 1448 ≠ 0, we apply division lemma to 1054 and 1448, to get
1448 = 1054 x 1 + 394
Step 3: We consider the new divisor 1054 and the new remainder 394, and apply the division lemma to get
1054 = 394 x 2 + 266
We consider the new divisor 394 and the new remainder 266,and apply the division lemma to get
394 = 266 x 1 + 128
We consider the new divisor 266 and the new remainder 128,and apply the division lemma to get
266 = 128 x 2 + 10
We consider the new divisor 128 and the new remainder 10,and apply the division lemma to get
128 = 10 x 12 + 8
We consider the new divisor 10 and the new remainder 8,and apply the division lemma to get
10 = 8 x 1 + 2
We consider the new divisor 8 and the new remainder 2,and apply the division lemma to get
8 = 2 x 4 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 2, the HCF of 2502 and 1448 is 2
Notice that 2 = HCF(8,2) = HCF(10,8) = HCF(128,10) = HCF(266,128) = HCF(394,266) = HCF(1054,394) = HCF(1448,1054) = HCF(2502,1448) .
We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma
Step 1: Since 82731 > 2, we apply the division lemma to 82731 and 2, to get
82731 = 2 x 41365 + 1
Step 2: Since the reminder 2 ≠ 0, we apply division lemma to 1 and 2, to get
2 = 1 x 2 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 2 and 82731 is 1
Notice that 1 = HCF(2,1) = HCF(82731,2) .
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Frequently Asked Questions on HCF of 2502, 1448, 82731 using Euclid's Algorithm
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 2502, 1448, 82731?
Answer: HCF of 2502, 1448, 82731 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 2502, 1448, 82731 using Euclid's Algorithm?
Answer: For arbitrary numbers 2502, 1448, 82731 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.