Highest Common Factor of 255, 171 using Euclid's algorithm
Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 255, 171 i.e. 3 the largest integer that leaves a remainder zero for all numbers.
HCF of 255, 171 is 3 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 255, 171 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 255, 171 is 3.
HCF(255, 171) = 3
HCF of 255, 171 using Euclid's algorithm
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 255, 171 is 3.
Highest Common Factor of 255,171 is 3
Step 1: Since 255 > 171, we apply the division lemma to 255 and 171, to get
255 = 171 x 1 + 84
Step 2: Since the reminder 171 ≠ 0, we apply division lemma to 84 and 171, to get
171 = 84 x 2 + 3
Step 3: We consider the new divisor 84 and the new remainder 3, and apply the division lemma to get
84 = 3 x 28 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 3, the HCF of 255 and 171 is 3
Notice that 3 = HCF(84,3) = HCF(171,84) = HCF(255,171) .
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Frequently Asked Questions on HCF of 255, 171 using Euclid's Algorithm
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 255, 171?
Answer: HCF of 255, 171 is 3 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 255, 171 using Euclid's Algorithm?
Answer: For arbitrary numbers 255, 171 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.