Highest Common Factor of 2710, 637 using Euclid's algorithm

Created By : Jatin Gogia

Reviewed By : Rajasekhar Valipishetty

Last Updated : Apr 06, 2023


HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 2710, 637 i.e. 1 the largest integer that leaves a remainder zero for all numbers.

HCF of 2710, 637 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.

Consider we have numbers 2710, 637 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b

Highest common factor (HCF) of 2710, 637 is 1.

HCF(2710, 637) = 1

HCF of 2710, 637 using Euclid's algorithm

Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.

HCF of:

Highest common factor (HCF) of 2710, 637 is 1.

Highest Common Factor of 2710,637 using Euclid's algorithm

Highest Common Factor of 2710,637 is 1

Step 1: Since 2710 > 637, we apply the division lemma to 2710 and 637, to get

2710 = 637 x 4 + 162

Step 2: Since the reminder 637 ≠ 0, we apply division lemma to 162 and 637, to get

637 = 162 x 3 + 151

Step 3: We consider the new divisor 162 and the new remainder 151, and apply the division lemma to get

162 = 151 x 1 + 11

We consider the new divisor 151 and the new remainder 11,and apply the division lemma to get

151 = 11 x 13 + 8

We consider the new divisor 11 and the new remainder 8,and apply the division lemma to get

11 = 8 x 1 + 3

We consider the new divisor 8 and the new remainder 3,and apply the division lemma to get

8 = 3 x 2 + 2

We consider the new divisor 3 and the new remainder 2,and apply the division lemma to get

3 = 2 x 1 + 1

We consider the new divisor 2 and the new remainder 1,and apply the division lemma to get

2 = 1 x 2 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 2710 and 637 is 1

Notice that 1 = HCF(2,1) = HCF(3,2) = HCF(8,3) = HCF(11,8) = HCF(151,11) = HCF(162,151) = HCF(637,162) = HCF(2710,637) .

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Frequently Asked Questions on HCF of 2710, 637 using Euclid's Algorithm

1. What is the Euclid division algorithm?

Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.

2. what is the HCF of 2710, 637?

Answer: HCF of 2710, 637 is 1 the largest number that divides all the numbers leaving a remainder zero.

3. How to find HCF of 2710, 637 using Euclid's Algorithm?

Answer: For arbitrary numbers 2710, 637 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.