Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 302, 49539 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 302, 49539 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 302, 49539 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 302, 49539 is 1.
HCF(302, 49539) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 302, 49539 is 1.
Step 1: Since 49539 > 302, we apply the division lemma to 49539 and 302, to get
49539 = 302 x 164 + 11
Step 2: Since the reminder 302 ≠ 0, we apply division lemma to 11 and 302, to get
302 = 11 x 27 + 5
Step 3: We consider the new divisor 11 and the new remainder 5, and apply the division lemma to get
11 = 5 x 2 + 1
We consider the new divisor 5 and the new remainder 1, and apply the division lemma to get
5 = 1 x 5 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 302 and 49539 is 1
Notice that 1 = HCF(5,1) = HCF(11,5) = HCF(302,11) = HCF(49539,302) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 302, 49539?
Answer: HCF of 302, 49539 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 302, 49539 using Euclid's Algorithm?
Answer: For arbitrary numbers 302, 49539 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.