Highest Common Factor of 311, 115, 510, 34 using Euclid's algorithm
Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 311, 115, 510, 34 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 311, 115, 510, 34 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 311, 115, 510, 34 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 311, 115, 510, 34 is 1.
HCF(311, 115, 510, 34) = 1
HCF of 311, 115, 510, 34 using Euclid's algorithm
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 311, 115, 510, 34 is 1.
Highest Common Factor of 311,115,510,34 is 1
Step 1: Since 311 > 115, we apply the division lemma to 311 and 115, to get
311 = 115 x 2 + 81
Step 2: Since the reminder 115 ≠ 0, we apply division lemma to 81 and 115, to get
115 = 81 x 1 + 34
Step 3: We consider the new divisor 81 and the new remainder 34, and apply the division lemma to get
81 = 34 x 2 + 13
We consider the new divisor 34 and the new remainder 13,and apply the division lemma to get
34 = 13 x 2 + 8
We consider the new divisor 13 and the new remainder 8,and apply the division lemma to get
13 = 8 x 1 + 5
We consider the new divisor 8 and the new remainder 5,and apply the division lemma to get
8 = 5 x 1 + 3
We consider the new divisor 5 and the new remainder 3,and apply the division lemma to get
5 = 3 x 1 + 2
We consider the new divisor 3 and the new remainder 2,and apply the division lemma to get
3 = 2 x 1 + 1
We consider the new divisor 2 and the new remainder 1,and apply the division lemma to get
2 = 1 x 2 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 311 and 115 is 1
Notice that 1 = HCF(2,1) = HCF(3,2) = HCF(5,3) = HCF(8,5) = HCF(13,8) = HCF(34,13) = HCF(81,34) = HCF(115,81) = HCF(311,115) .
We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma
Step 1: Since 510 > 1, we apply the division lemma to 510 and 1, to get
510 = 1 x 510 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 510 is 1
Notice that 1 = HCF(510,1) .
We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma
Step 1: Since 34 > 1, we apply the division lemma to 34 and 1, to get
34 = 1 x 34 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 1 and 34 is 1
Notice that 1 = HCF(34,1) .
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Frequently Asked Questions on HCF of 311, 115, 510, 34 using Euclid's Algorithm
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 311, 115, 510, 34?
Answer: HCF of 311, 115, 510, 34 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 311, 115, 510, 34 using Euclid's Algorithm?
Answer: For arbitrary numbers 311, 115, 510, 34 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.