Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 330, 737 i.e. 11 the largest integer that leaves a remainder zero for all numbers.
HCF of 330, 737 is 11 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 330, 737 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 330, 737 is 11.
HCF(330, 737) = 11
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 330, 737 is 11.
Step 1: Since 737 > 330, we apply the division lemma to 737 and 330, to get
737 = 330 x 2 + 77
Step 2: Since the reminder 330 ≠ 0, we apply division lemma to 77 and 330, to get
330 = 77 x 4 + 22
Step 3: We consider the new divisor 77 and the new remainder 22, and apply the division lemma to get
77 = 22 x 3 + 11
We consider the new divisor 22 and the new remainder 11, and apply the division lemma to get
22 = 11 x 2 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 11, the HCF of 330 and 737 is 11
Notice that 11 = HCF(22,11) = HCF(77,22) = HCF(330,77) = HCF(737,330) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 330, 737?
Answer: HCF of 330, 737 is 11 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 330, 737 using Euclid's Algorithm?
Answer: For arbitrary numbers 330, 737 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.