Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 331, 552 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 331, 552 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 331, 552 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 331, 552 is 1.
HCF(331, 552) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 331, 552 is 1.
Step 1: Since 552 > 331, we apply the division lemma to 552 and 331, to get
552 = 331 x 1 + 221
Step 2: Since the reminder 331 ≠ 0, we apply division lemma to 221 and 331, to get
331 = 221 x 1 + 110
Step 3: We consider the new divisor 221 and the new remainder 110, and apply the division lemma to get
221 = 110 x 2 + 1
We consider the new divisor 110 and the new remainder 1, and apply the division lemma to get
110 = 1 x 110 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 331 and 552 is 1
Notice that 1 = HCF(110,1) = HCF(221,110) = HCF(331,221) = HCF(552,331) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 331, 552?
Answer: HCF of 331, 552 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 331, 552 using Euclid's Algorithm?
Answer: For arbitrary numbers 331, 552 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.