Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 369, 318 i.e. 3 the largest integer that leaves a remainder zero for all numbers.
HCF of 369, 318 is 3 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 369, 318 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 369, 318 is 3.
HCF(369, 318) = 3
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 369, 318 is 3.
Step 1: Since 369 > 318, we apply the division lemma to 369 and 318, to get
369 = 318 x 1 + 51
Step 2: Since the reminder 318 ≠ 0, we apply division lemma to 51 and 318, to get
318 = 51 x 6 + 12
Step 3: We consider the new divisor 51 and the new remainder 12, and apply the division lemma to get
51 = 12 x 4 + 3
We consider the new divisor 12 and the new remainder 3, and apply the division lemma to get
12 = 3 x 4 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 3, the HCF of 369 and 318 is 3
Notice that 3 = HCF(12,3) = HCF(51,12) = HCF(318,51) = HCF(369,318) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 369, 318?
Answer: HCF of 369, 318 is 3 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 369, 318 using Euclid's Algorithm?
Answer: For arbitrary numbers 369, 318 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.